251113005041 has 4 divisors (see below), whose sum is σ = 251114165232. Its totient is φ = 251111844852.

The previous prime is 251113005023. The next prime is 251113005083. The reversal of 251113005041 is 140500311152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 251113005041 - 2¹⁰ = 251113004017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 251113004998 and 251113005016.

It is not an unprimeable number, because it can be changed into a prime (251113005841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148295 + ... + 724028.

It is an arithmetic number, because the mean of its divisors is an integer number (62778541308).

Almost surely, 2^251113005041 is an apocalyptic number.

It is an amenable number.

251113005041 is a deficient number, since it is larger than the sum of its proper divisors (1160191).

251113005041 is an equidigital number, since it uses as much as digits as its factorization.

251113005041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1160190.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 251113005041 its reverse (140500311152), we get a palindrome (391613316193).

The spelling of 251113005041 in words is "two hundred fifty-one billion, one hundred thirteen million, five thousand, forty-one".