Base | Representation |
---|---|
bin | 10111011001011101… |
… | …011011010100100001 |
3 | 2101211212202010021011 |
4 | 113121131123110201 |
5 | 402423020101213 |
6 | 15312541300521 |
7 | 1546401505543 |
oct | 273135332441 |
9 | 71755663234 |
10 | 25123206433 |
11 | a722438926 |
12 | 4a51864741 |
13 | 24a4c13a30 |
14 | 1304899693 |
15 | 9c090d03d |
hex | 5d975b521 |
25123206433 has 8 divisors (see below), whose sum is σ = 27058477376. Its totient is φ = 23188323600.
The previous prime is 25123206413. The next prime is 25123206457. The reversal of 25123206433 is 33460232152.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 25123206433 - 25 = 25123206401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25123206395 and 25123206404.
It is not an unprimeable number, because it can be changed into a prime (25123206413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45148 + ... + 228658.
It is an arithmetic number, because the mean of its divisors is an integer number (3382309672).
Almost surely, 225123206433 is an apocalyptic number.
It is an amenable number.
25123206433 is a deficient number, since it is larger than the sum of its proper divisors (1935270943).
25123206433 is a wasteful number, since it uses less digits than its factorization.
25123206433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 194055.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 25123206433 its reverse (33460232152), we get a palindrome (58583438585).
The spelling of 25123206433 in words is "twenty-five billion, one hundred twenty-three million, two hundred six thousand, four hundred thirty-three".
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