Base | Representation |
---|---|
bin | 10111011001100100… |
… | …101010100110000001 |
3 | 2101212000022112020110 |
4 | 113121210222212001 |
5 | 402424011312001 |
6 | 15313050101533 |
7 | 1546423601034 |
oct | 273144524601 |
9 | 71760275213 |
10 | 25125104001 |
11 | a723514568 |
12 | 4a5241a8a9 |
13 | 24a542965a |
14 | 1304c3101b |
15 | 9c0b853d6 |
hex | 5d992a981 |
25125104001 has 4 divisors (see below), whose sum is σ = 33500138672. Its totient is φ = 16750069332.
The previous prime is 25125103973. The next prime is 25125104023. The reversal of 25125104001 is 10040152152.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 25125104001 - 218 = 25124841857 is a prime.
It is a super-2 number, since 2×251251040012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25125104041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4187517331 + ... + 4187517336.
It is an arithmetic number, because the mean of its divisors is an integer number (8375034668).
Almost surely, 225125104001 is an apocalyptic number.
It is an amenable number.
25125104001 is a deficient number, since it is larger than the sum of its proper divisors (8375034671).
25125104001 is an equidigital number, since it uses as much as digits as its factorization.
25125104001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8375034670.
The product of its (nonzero) digits is 400, while the sum is 21.
Adding to 25125104001 its reverse (10040152152), we get a palindrome (35165256153).
The spelling of 25125104001 in words is "twenty-five billion, one hundred twenty-five million, one hundred four thousand, one".
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