Search a number
-
+
25130050737 = 3111297587137
BaseRepresentation
bin10111011001110111…
…100010010010110001
32101212100121211212220
4113121313202102301
5402431243110422
615313344111253
71546513623021
oct273167422261
971770554786
1025130050737
11a726293080
124a54005529
1324a646c10c
14130575ba81
159c1310e5c
hex5d9de24b1

25130050737 has 16 divisors (see below), whose sum is σ = 36581045952. Its totient is φ = 15218565120.

The previous prime is 25130050721. The next prime is 25130050741. The reversal of 25130050737 is 73705003152.

It is not a de Polignac number, because 25130050737 - 24 = 25130050721 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 25130050698 and 25130050707.

It is not an unprimeable number, because it can be changed into a prime (25130050537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 250768 + ... + 336369.

It is an arithmetic number, because the mean of its divisors is an integer number (2286315372).

Almost surely, 225130050737 is an apocalyptic number.

It is an amenable number.

25130050737 is a deficient number, since it is larger than the sum of its proper divisors (11450995215).

25130050737 is a wasteful number, since it uses less digits than its factorization.

25130050737 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 588448.

The product of its (nonzero) digits is 22050, while the sum is 33.

Adding to 25130050737 its reverse (73705003152), we get a palindrome (98835053889).

The spelling of 25130050737 in words is "twenty-five billion, one hundred thirty million, fifty thousand, seven hundred thirty-seven".

Divisors: 1 3 11 33 1297 3891 14267 42801 587137 1761411 6458507 19375521 761516689 2284550067 8376683579 25130050737