25131141211 has 4 divisors (see below), whose sum is σ = 27415790424. Its totient is φ = 22846492000.

The previous prime is 25131141143. The next prime is 25131141247. The reversal of 25131141211 is 11214113152.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25131141211 - 2¹³ = 25131133019 is a prime.

It is a super-3 number, since 3×25131141211³ (a number of 32 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (25131141271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1142324590 + ... + 1142324611.

It is an arithmetic number, because the mean of its divisors is an integer number (6853947606).

Almost surely, 2^25131141211 is an apocalyptic number.

25131141211 is a deficient number, since it is larger than the sum of its proper divisors (2284649213).

25131141211 is a wasteful number, since it uses less digits than its factorization.

25131141211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2284649212.

The product of its digits is 240, while the sum is 22.

Adding to 25131141211 its reverse (11214113152), we get a palindrome (36345254363).

The spelling of 25131141211 in words is "twenty-five billion, one hundred thirty-one million, one hundred forty-one thousand, two hundred eleven".