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2513201113 = 5714401403
BaseRepresentation
bin1001010111001100…
…0110011111011001
320111011000211210201
42111303012133121
520121334413423
61053214342201
7116164566643
oct22563063731
96434024721
102513201113
11107a700215
125a17ba961
133108a2067
1419bac9893
15ea9872ad
hex95cc67d9

2513201113 has 4 divisors (see below), whose sum is σ = 2517603088. Its totient is φ = 2508799140.

The previous prime is 2513201101. The next prime is 2513201233. The reversal of 2513201113 is 3111023152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2513201113 - 25 = 2513201081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2513202113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200131 + ... + 2201272.

It is an arithmetic number, because the mean of its divisors is an integer number (629400772).

Almost surely, 22513201113 is an apocalyptic number.

It is an amenable number.

2513201113 is a deficient number, since it is larger than the sum of its proper divisors (4401975).

2513201113 is an equidigital number, since it uses as much as digits as its factorization.

2513201113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4401974.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 2513201113 is about 50131.8373192126. The cubic root of 2513201113 is about 1359.5935047027.

Adding to 2513201113 its reverse (3111023152), we get a palindrome (5624224265).

The spelling of 2513201113 in words is "two billion, five hundred thirteen million, two hundred one thousand, one hundred thirteen".

Divisors: 1 571 4401403 2513201113