Base | Representation |
---|---|
bin | 1011011011011100110010… |
… | …10010000110111101011011 |
3 | 10021222122011221011101121122 |
4 | 11231232121102012331123 |
5 | 11243232201334410133 |
6 | 125241402104355455 |
7 | 5202520633241132 |
oct | 555563122067533 |
9 | 107878157141548 |
10 | 25132425310043 |
11 | 800a668982a97 |
12 | 299a9ba475b8b |
13 | 1103c9285a80c |
14 | 62c5b723a919 |
15 | 2d8b432e1498 |
hex | 16db99486f5b |
25132425310043 has 4 divisors (see below), whose sum is σ = 25132438288848. Its totient is φ = 25132412331240.
The previous prime is 25132425310019. The next prime is 25132425310061. The reversal of 25132425310043 is 34001352423152.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25132425310043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25132425309985 and 25132425310012.
It is not an unprimeable number, because it can be changed into a prime (25132425310243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2936303 + ... + 7673768.
It is an arithmetic number, because the mean of its divisors is an integer number (6283109572212).
Almost surely, 225132425310043 is an apocalyptic number.
25132425310043 is a deficient number, since it is larger than the sum of its proper divisors (12978805).
25132425310043 is a wasteful number, since it uses less digits than its factorization.
25132425310043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12978804.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 25132425310043 its reverse (34001352423152), we get a palindrome (59133777733195).
The spelling of 25132425310043 in words is "twenty-five trillion, one hundred thirty-two billion, four hundred twenty-five million, three hundred ten thousand, forty-three".
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