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2514010001 = 5942610339
BaseRepresentation
bin1001010111011000…
…1011111110010001
320111012112221101112
42111312023332101
520122041310001
61053243543105
7116204506136
oct22566137621
96435487345
102514010001
111080102a18
125a1b2aa95
13310ac62a9
1419bc5a58d
15eaa96cbb
hex95d8bf91

2514010001 has 4 divisors (see below), whose sum is σ = 2556620400. Its totient is φ = 2471399604.

The previous prime is 2514009977. The next prime is 2514010033. The reversal of 2514010001 is 1000104152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2514010001 - 26 = 2514009937 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2514210001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21305111 + ... + 21305228.

It is an arithmetic number, because the mean of its divisors is an integer number (639155100).

Almost surely, 22514010001 is an apocalyptic number.

It is an amenable number.

2514010001 is a deficient number, since it is larger than the sum of its proper divisors (42610399).

2514010001 is an equidigital number, since it uses as much as digits as its factorization.

2514010001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42610398.

The product of its (nonzero) digits is 40, while the sum is 14.

The square root of 2514010001 is about 50139.9042779302. The cubic root of 2514010001 is about 1359.7393533442.

Adding to 2514010001 its reverse (1000104152), we get a palindrome (3514114153).

The spelling of 2514010001 in words is "two billion, five hundred fourteen million, ten thousand, one".

Divisors: 1 59 42610339 2514010001