251401414139 has 4 divisors (see below), whose sum is σ = 251410982424. Its totient is φ = 251391845856.

The previous prime is 251401414127. The next prime is 251401414151. The reversal of 251401414139 is 931414104152.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (251401414127) and next prime (251401414151).

It is a cyclic number.

It is not a de Polignac number, because 251401414139 - 2³² = 247106446843 is a prime.

It is a super-3 number, since 3×251401414139³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 251401414099 and 251401414108.

It is not an unprimeable number, because it can be changed into a prime (251401414639) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4744622 + ... + 4797315.

It is an arithmetic number, because the mean of its divisors is an integer number (62852745606).

Almost surely, 2^251401414139 is an apocalyptic number.

251401414139 is a deficient number, since it is larger than the sum of its proper divisors (9568285).

251401414139 is an equidigital number, since it uses as much as digits as its factorization.

251401414139 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9568284.

The product of its (nonzero) digits is 17280, while the sum is 35.

The spelling of 251401414139 in words is "two hundred fifty-one billion, four hundred one million, four hundred fourteen thousand, one hundred thirty-nine".