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25140403 = 231093061
BaseRepresentation
bin101111111100…
…1110010110011
31202022021011001
41133321302303
522413443103
62254502431
7423455431
oct137716263
952267131
1025140403
11132113a2
128504a17
1352930a2
1434a5d51
15231901d
hex17f9cb3

25140403 has 4 divisors (see below), whose sum is σ = 26233488. Its totient is φ = 24047320.

The previous prime is 25140389. The next prime is 25140457. The reversal of 25140403 is 30404152.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25140403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25140463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546508 + ... + 546553.

It is an arithmetic number, because the mean of its divisors is an integer number (6558372).

Almost surely, 225140403 is an apocalyptic number.

25140403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

25140403 is a deficient number, since it is larger than the sum of its proper divisors (1093085).

25140403 is a wasteful number, since it uses less digits than its factorization.

25140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1093084.

The product of its (nonzero) digits is 480, while the sum is 19.

The square root of 25140403 is about 5014.0206421593. The cubic root of 25140403 is about 292.9481400914.

Adding to 25140403 its reverse (30404152), we get a palindrome (55544555).

The spelling of 25140403 in words is "twenty-five million, one hundred forty thousand, four hundred three".

Divisors: 1 23 1093061 25140403