251424442131 has 4 divisors (see below), whose sum is σ = 335232589512. Its totient is φ = 167616294752.

The previous prime is 251424442097. The next prime is 251424442151. The reversal of 251424442131 is 131244424152.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 251424442131 - 2¹⁸ = 251424179987 is a prime.

It is a super-2 number, since 2×251424442131² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 251424442092 and 251424442101.

It is not an unprimeable number, because it can be changed into a prime (251424442151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41904073686 + ... + 41904073691.

It is an arithmetic number, because the mean of its divisors is an integer number (83808147378).

Almost surely, 2^251424442131 is an apocalyptic number.

251424442131 is a deficient number, since it is larger than the sum of its proper divisors (83808147381).

251424442131 is an equidigital number, since it uses as much as digits as its factorization.

251424442131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83808147380.

The product of its digits is 30720, while the sum is 33.

Adding to 251424442131 its reverse (131244424152), we get a palindrome (382668866283).

The spelling of 251424442131 in words is "two hundred fifty-one billion, four hundred twenty-four million, four hundred forty-two thousand, one hundred thirty-one".