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25149118993 = 3112743914551
BaseRepresentation
bin10111011011000000…
…010001101000010001
32101220200111121121121
4113123000101220101
5403001133301433
615315304522241
71550134661425
oct273300215021
971820447547
1025149118993
11a736027369
124a5a480381
1324aa3b73cb
1413080c2b85
159c2d2ac2d
hex5db011a11

25149118993 has 16 divisors (see below), whose sum is σ = 26226196480. Its totient is φ = 24089562000.

The previous prime is 25149118991. The next prime is 25149119053. The reversal of 25149118993 is 39981194152.

It is a cyclic number.

It is not a de Polignac number, because 25149118993 - 21 = 25149118991 is a prime.

It is a super-3 number, since 3×251491189933 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25149118993.

It is not an unprimeable number, because it can be changed into a prime (25149118991) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1721068 + ... + 1735618.

It is an arithmetic number, because the mean of its divisors is an integer number (1639137280).

Almost surely, 225149118993 is an apocalyptic number.

It is an amenable number.

25149118993 is a deficient number, since it is larger than the sum of its proper divisors (1077077487).

25149118993 is a wasteful number, since it uses less digits than its factorization.

25149118993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15148.

The product of its digits is 699840, while the sum is 52.

The spelling of 25149118993 in words is "twenty-five billion, one hundred forty-nine million, one hundred eighteen thousand, nine hundred ninety-three".

Divisors: 1 31 127 439 3937 13609 14551 55753 451081 1728343 1847977 6387889 57287287 198024559 811261903 25149118993