252013434131 has 4 divisors (see below), whose sum is σ = 252031860432. Its totient is φ = 251995007832.

The previous prime is 252013434121. The next prime is 252013434139. The reversal of 252013434131 is 131434310252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-252013434131 is a prime.

It is a super-2 number, since 2×252013434131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 252013434094 and 252013434103.

It is not an unprimeable number, because it can be changed into a prime (252013434139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9192620 + ... + 9219993.

It is an arithmetic number, because the mean of its divisors is an integer number (63007965108).

Almost surely, 2^252013434131 is an apocalyptic number.

252013434131 is a deficient number, since it is larger than the sum of its proper divisors (18426301).

252013434131 is a wasteful number, since it uses less digits than its factorization.

252013434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18426300.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 252013434131 its reverse (131434310252), we get a palindrome (383447744383).

The spelling of 252013434131 in words is "two hundred fifty-two billion, thirteen million, four hundred thirty-four thousand, one hundred thirty-one".