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2521214335041 = 323138469263881
BaseRepresentation
bin100100101100000100000…
…101011011100001000001
322221000200202120102222020
4210230010011123201001
5312301421332210131
65210121353032053
7350103020152623
oct44540405334101
98830622512866
102521214335041
11892271845186
123487656b5629
1315399882cccc
148a05537ac13
15458b1299996
hex24b0415b841

2521214335041 has 16 divisors (see below), whose sum is σ = 3507815091840. Its totient is φ = 1607713176960.

The previous prime is 2521214335037. The next prime is 2521214335043. The reversal of 2521214335041 is 1405334121252.

It is not a de Polignac number, because 2521214335041 - 22 = 2521214335037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2521214334993 and 2521214335011.

It is not an unprimeable number, because it can be changed into a prime (2521214335043) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9422421 + ... + 9686301.

It is an arithmetic number, because the mean of its divisors is an integer number (219238443240).

Almost surely, 22521214335041 is an apocalyptic number.

It is an amenable number.

2521214335041 is a deficient number, since it is larger than the sum of its proper divisors (986600756799).

2521214335041 is a wasteful number, since it uses less digits than its factorization.

2521214335041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402376.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 2521214335041 its reverse (1405334121252), we get a palindrome (3926548456293).

The spelling of 2521214335041 in words is "two trillion, five hundred twenty-one billion, two hundred fourteen million, three hundred thirty-five thousand, forty-one".

Divisors: 1 3 23 69 138469 263881 415407 791643 3184787 6069263 9554361 18207789 36539338189 109618014567 840404778347 2521214335041