2523000113 has 4 divisors (see below), whose sum is σ = 2523115248. Its totient is φ = 2522884980.

The previous prime is 2523000089. The next prime is 2523000119. The reversal of 2523000113 is 3110003252.

2523000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2523000113 - 2⁶ = 2523000049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2523000091 and 2523000100.

It is not an unprimeable number, because it can be changed into a prime (2523000119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13403 + ... + 72288.

It is an arithmetic number, because the mean of its divisors is an integer number (630778812).

Almost surely, 2^2523000113 is an apocalyptic number.

It is an amenable number.

2523000113 is a deficient number, since it is larger than the sum of its proper divisors (115135).

2523000113 is an equidigital number, since it uses as much as digits as its factorization.

2523000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115134.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 2523000113 is about 50229.4745443350. The cubic root of 2523000113 is about 1361.3582366786.

Adding to 2523000113 its reverse (3110003252), we get a palindrome (5633003365).

The spelling of 2523000113 in words is "two billion, five hundred twenty-three million, one hundred thirteen", and thus it is an aban number.