Base | Representation |
---|---|
bin | 111001011001000101000010… |
… | …001110000011111100001011 |
3 | 1020002201100121100010012002120 |
4 | 321121011002032003330023 |
5 | 231041004331231013120 |
6 | 2252500254152502323 |
7 | 104111111516542452 |
oct | 7131050216037413 |
9 | 1202640540105076 |
10 | 252412044001035 |
11 | 7347638a519886 |
12 | 2438718a9aa9a3 |
13 | aaac479b83a89 |
14 | 4648b45673b99 |
15 | 1e2ac3ab38140 |
hex | e59142383f0b |
252412044001035 has 8 divisors (see below), whose sum is σ = 403859270401680. Its totient is φ = 134619756800544.
The previous prime is 252412044001003. The next prime is 252412044001063. The reversal of 252412044001035 is 530100440214252.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 252412044001035 - 25 = 252412044001003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 252412044000987 and 252412044001005.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8413734800020 + ... + 8413734800049.
It is an arithmetic number, because the mean of its divisors is an integer number (50482408800210).
Almost surely, 2252412044001035 is an apocalyptic number.
252412044001035 is a deficient number, since it is larger than the sum of its proper divisors (151447226400645).
252412044001035 is a wasteful number, since it uses less digits than its factorization.
252412044001035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16827469600077.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 252412044001035 its reverse (530100440214252), we get a palindrome (782512484215287).
The spelling of 252412044001035 in words is "two hundred fifty-two trillion, four hundred twelve billion, forty-four million, one thousand, thirty-five".
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