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252545124113 = 1039243065567
BaseRepresentation
bin1110101100110011011…
…1001100011100010001
3220010212022012120001022
43223030313030130101
513114203022432423
6312003450245225
724150206064452
oct3531467143421
9803768176038
10252545124113
1198116158707
1240b40a26815
131aa7945a2a9
14c31a84b129
1568814a9dc8
hex3accdcc711

252545124113 has 4 divisors (see below), whose sum is σ = 252788190720. Its totient is φ = 252302057508.

The previous prime is 252545124071. The next prime is 252545124121. The reversal of 252545124113 is 311421545252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 252545124113 - 214 = 252545107729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (252545124133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121531745 + ... + 121533822.

It is an arithmetic number, because the mean of its divisors is an integer number (63197047680).

Almost surely, 2252545124113 is an apocalyptic number.

It is an amenable number.

252545124113 is a deficient number, since it is larger than the sum of its proper divisors (243066607).

252545124113 is a wasteful number, since it uses less digits than its factorization.

252545124113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243066606.

The product of its digits is 48000, while the sum is 35.

Adding to 252545124113 its reverse (311421545252), we get a palindrome (563966669365).

The spelling of 252545124113 in words is "two hundred fifty-two billion, five hundred forty-five million, one hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 1039 243065567 252545124113