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2525500305051 = 3841833435017
BaseRepresentation
bin100100110000000011100…
…011000110111010011011
322221102202110101021112020
4210300003203012322123
5312334211034230201
65212110540145523
7350314152253203
oct44600343067233
98842673337466
102525500305051
1189407109a959
12349560b382a3
131541cc779539
148a340691403
1545a626aba36
hex24c038c6e9b

2525500305051 has 4 divisors (see below), whose sum is σ = 3367333740072. Its totient is φ = 1683666870032.

The previous prime is 2525500304941. The next prime is 2525500305061. The reversal of 2525500305051 is 1505030055252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2525500305051 is a prime.

It is a super-3 number, since 3×25255003050513 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (2525500305061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420916717506 + ... + 420916717511.

It is an arithmetic number, because the mean of its divisors is an integer number (841833435018).

Almost surely, 22525500305051 is an apocalyptic number.

2525500305051 is a deficient number, since it is larger than the sum of its proper divisors (841833435021).

2525500305051 is an equidigital number, since it uses as much as digits as its factorization.

2525500305051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 841833435020.

The product of its (nonzero) digits is 37500, while the sum is 33.

The spelling of 2525500305051 in words is "two trillion, five hundred twenty-five billion, five hundred million, three hundred five thousand, fifty-one".

Divisors: 1 3 841833435017 2525500305051