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252914057 = 1122992187
BaseRepresentation
bin11110001001100…
…10100110001001
3122121220100212022
433010302212021
51004221222212
641032454225
76160506524
oct1704624611
9577810768
10252914057
1111a844090
127084a375
1340522bb6
1425837bbb
151730c772
hexf132989

252914057 has 4 divisors (see below), whose sum is σ = 275906256. Its totient is φ = 229921860.

The previous prime is 252914047. The next prime is 252914071. The reversal of 252914057 is 750419252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 252914057 - 26 = 252913993 is a prime.

It is a super-3 number, since 3×2529140573 (a number of 26 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (252914047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11496083 + ... + 11496104.

It is an arithmetic number, because the mean of its divisors is an integer number (68976564).

Almost surely, 2252914057 is an apocalyptic number.

It is an amenable number.

252914057 is a deficient number, since it is larger than the sum of its proper divisors (22992199).

252914057 is a wasteful number, since it uses less digits than its factorization.

252914057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22992198.

The product of its (nonzero) digits is 25200, while the sum is 35.

The square root of 252914057 is about 15903.2718960596. The cubic root of 252914057 is about 632.3987304212.

The spelling of 252914057 in words is "two hundred fifty-two million, nine hundred fourteen thousand, fifty-seven".

Divisors: 1 11 22992187 252914057