Base | Representation |
---|---|
bin | 100100110101010010100… |
… | …010001100110000111011 |
3 | 22221222021010122102101222 |
4 | 210311102202030300323 |
5 | 312432213312343420 |
6 | 5214440343102255 |
7 | 350603344464401 |
oct | 44652242146073 |
9 | 8858233572358 |
10 | 2531120434235 |
11 | 896495554118 |
12 | 34a66b14198b |
13 | 1548b6c30b73 |
14 | 8a714c59471 |
15 | 45c90caa225 |
hex | 24d5288cc3b |
2531120434235 has 16 divisors (see below), whose sum is σ = 3047150535264. Its totient is φ = 2018367866112.
The previous prime is 2531120434133. The next prime is 2531120434247. The reversal of 2531120434235 is 5324340211352.
It is a cyclic number.
It is not a de Polignac number, because 2531120434235 - 226 = 2531053325371 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2531120434195 and 2531120434204.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1734989 + ... + 2841201.
It is an arithmetic number, because the mean of its divisors is an integer number (190446908454).
Almost surely, 22531120434235 is an apocalyptic number.
2531120434235 is a deficient number, since it is larger than the sum of its proper divisors (516030101029).
2531120434235 is a wasteful number, since it uses less digits than its factorization.
2531120434235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1107694.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 2531120434235 its reverse (5324340211352), we get a palindrome (7855460645587).
The spelling of 2531120434235 in words is "two trillion, five hundred thirty-one billion, one hundred twenty million, four hundred thirty-four thousand, two hundred thirty-five".
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