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2531401 = 7433407
BaseRepresentation
bin1001101010000001001001
311202121102121
421222001021
51122001101
6130131241
730342115
oct11520111
94677377
102531401
111479974
12a20b21
136a8292
1449c745
153500a1
hex26a049

2531401 has 4 divisors (see below), whose sum is σ = 2535552. Its totient is φ = 2527252.

The previous prime is 2531393. The next prime is 2531413. The reversal of 2531401 is 1041352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2531401 - 23 = 2531393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2531471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 961 + ... + 2446.

It is an arithmetic number, because the mean of its divisors is an integer number (633888).

22531401 is an apocalyptic number.

It is an amenable number.

2531401 is a deficient number, since it is larger than the sum of its proper divisors (4151).

2531401 is an equidigital number, since it uses as much as digits as its factorization.

2531401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4150.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 2531401 is about 1591.0377116838. The cubic root of 2531401 is about 136.2867543859.

Subtracting from 2531401 its product of nonzero digits (120), we obtain a square (2531281 = 15912).

Adding to 2531401 its reverse (1041352), we get a palindrome (3572753).

It can be divided in two parts, 253 and 1401, that multiplied together give a palindrome (354453).

The spelling of 2531401 in words is "two million, five hundred thirty-one thousand, four hundred one".

Divisors: 1 743 3407 2531401