Base | Representation |
---|---|
bin | 100100110101100100000… |
… | …010100010001001101011 |
3 | 22222000000121021100210220 |
4 | 210311210002202021223 |
5 | 312433314003414430 |
6 | 5214525433541123 |
7 | 350613542010243 |
oct | 44654402421153 |
9 | 8860017240726 |
10 | 2531414123115 |
11 | 8966263079a9 |
12 | 34a7315747a3 |
13 | 154932a2c177 |
14 | 8a741c68b23 |
15 | 45cab96e110 |
hex | 24d640a226b |
2531414123115 has 16 divisors (see below), whose sum is σ = 4110714279168. Its totient is φ = 1329936971616.
The previous prime is 2531414123101. The next prime is 2531414123177. The reversal of 2531414123115 is 5113214141352.
It is not a de Polignac number, because 2531414123115 - 210 = 2531414122091 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1259409007 + ... + 1259411016.
It is an arithmetic number, because the mean of its divisors is an integer number (256919642448).
Almost surely, 22531414123115 is an apocalyptic number.
2531414123115 is a deficient number, since it is larger than the sum of its proper divisors (1579300156053).
2531414123115 is a wasteful number, since it uses less digits than its factorization.
2531414123115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2518820098.
The product of its digits is 14400, while the sum is 33.
Adding to 2531414123115 its reverse (5113214141352), we get a palindrome (7644628264467).
The spelling of 2531414123115 in words is "two trillion, five hundred thirty-one billion, four hundred fourteen million, one hundred twenty-three thousand, one hundred fifteen".
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