25314211433 has 4 divisors (see below), whose sum is σ = 28930527360. Its totient is φ = 21697895508.

The previous prime is 25314211427. The next prime is 25314211463. The reversal of 25314211433 is 33411241352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25314211433 - 2¹⁰ = 25314210409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25314211396 and 25314211405.

It is not an unprimeable number, because it can be changed into a prime (25314211463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1808157953 + ... + 1808157966.

It is an arithmetic number, because the mean of its divisors is an integer number (7232631840).

Almost surely, 2^25314211433 is an apocalyptic number.

It is an amenable number.

25314211433 is a deficient number, since it is larger than the sum of its proper divisors (3616315927).

25314211433 is an equidigital number, since it uses as much as digits as its factorization.

25314211433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3616315926.

The product of its digits is 8640, while the sum is 29.

Adding to 25314211433 its reverse (33411241352), we get a palindrome (58725452785).

The spelling of 25314211433 in words is "twenty-five billion, three hundred fourteen million, two hundred eleven thousand, four hundred thirty-three".