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253146433 = 1272936803
BaseRepresentation
bin11110001011010…
…11010101000001
3122122100011121211
433011223111001
51004301141213
641041450121
76162465151
oct1705532501
9578304554
10253146433
1111a992731
1270940941
13405a48b7
1425898761
151735653d
hexf16b541

253146433 has 8 divisors (see below), whose sum is σ = 256048128. Its totient is φ = 250259184.

The previous prime is 253146427. The next prime is 253146457. The reversal of 253146433 is 334641352.

253146433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 253146433 - 225 = 219592001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 253146395 and 253146404.

It is not an unprimeable number, because it can be changed into a prime (253146463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33810 + ... + 40612.

It is an arithmetic number, because the mean of its divisors is an integer number (32006016).

Almost surely, 2253146433 is an apocalyptic number.

It is an amenable number.

253146433 is a deficient number, since it is larger than the sum of its proper divisors (2901695).

253146433 is a wasteful number, since it uses less digits than its factorization.

253146433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7223.

The product of its digits is 25920, while the sum is 31.

The square root of 253146433 is about 15910.5761366457. The cubic root of 253146433 is about 632.5923525883.

Adding to 253146433 its reverse (334641352), we get a palindrome (587787785).

The spelling of 253146433 in words is "two hundred fifty-three million, one hundred forty-six thousand, four hundred thirty-three".

Divisors: 1 127 293 6803 37211 863981 1993279 253146433