253153525441 has 4 divisors (see below), whose sum is σ = 253309122352. Its totient is φ = 252997928532.

The previous prime is 253153525411. The next prime is 253153525463. The reversal of 253153525441 is 144525351352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 253153525441 - 2¹⁷ = 253153394369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 253153525394 and 253153525403.

It is not an unprimeable number, because it can be changed into a prime (253153525411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77796015 + ... + 77799268.

It is an arithmetic number, because the mean of its divisors is an integer number (63327280588).

Almost surely, 2^253153525441 is an apocalyptic number.

It is an amenable number.

253153525441 is a deficient number, since it is larger than the sum of its proper divisors (155596911).

253153525441 is a wasteful number, since it uses less digits than its factorization.

253153525441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155596910.

The product of its digits is 360000, while the sum is 40.

Adding to 253153525441 its reverse (144525351352), we get a palindrome (397678876793).

The spelling of 253153525441 in words is "two hundred fifty-three billion, one hundred fifty-three million, five hundred twenty-five thousand, four hundred forty-one".