2532514041 has 6 divisors (see below), whose sum is σ = 3658075850. Its totient is φ = 1688342688.

The previous prime is 2532513967. The next prime is 2532514043. The reversal of 2532514041 is 1404152352.

2532514041 is a `hidden beast` number, since 2 + 5 + 3 + 251 + 404 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1267644816 + 1264869225 = 35604^2 + 35565^2 .

It is not a de Polignac number, because 2532514041 - 2⁷ = 2532513913 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2532513996 and 2532514014.

It is not an unprimeable number, because it can be changed into a prime (2532514043) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 140695216 + ... + 140695233.

Almost surely, 2^2532514041 is an apocalyptic number.

It is an amenable number.

2532514041 is a deficient number, since it is larger than the sum of its proper divisors (1125561809).

2532514041 is a wasteful number, since it uses less digits than its factorization.

2532514041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 281390455 (or 281390452 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 27.

The square root of 2532514041 is about 50324.0900662893. The cubic root of 2532514041 is about 1363.0672626683.

Adding to 2532514041 its reverse (1404152352), we get a palindrome (3936666393).

The spelling of 2532514041 in words is "two billion, five hundred thirty-two million, five hundred fourteen thousand, forty-one".