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25340435113 = 724112613457
BaseRepresentation
bin10111100110011010…
…000101101010101001
32102102000111110222211
4113212122011222221
5403344122410423
615350301245121
71554650100400
oct274632055251
972360443884
1025340435113
11a824018a64
124ab25637a1
13250ac20c06
141325684637
159d4a1c10d
hex5e6685aa9

25340435113 has 12 divisors (see below), whose sum is σ = 30196618452. Its totient is φ = 21190606080.

The previous prime is 25340435111. The next prime is 25340435123. The reversal of 25340435113 is 31153404352.

It can be written as a sum of positive squares in 2 ways, for example, as 6524277529 + 18816157584 = 80773^2 + 137172^2 .

It is not a de Polignac number, because 25340435113 - 21 = 25340435111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (25340435111) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6304720 + ... + 6308737.

It is an arithmetic number, because the mean of its divisors is an integer number (2516384871).

Almost surely, 225340435113 is an apocalyptic number.

It is an amenable number.

25340435113 is a deficient number, since it is larger than the sum of its proper divisors (4856183339).

25340435113 is a wasteful number, since it uses less digits than its factorization.

25340435113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12613512 (or 12613505 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 25340435113 its reverse (31153404352), we get a palindrome (56493839465).

The spelling of 25340435113 in words is "twenty-five billion, three hundred forty million, four hundred thirty-five thousand, one hundred thirteen".

Divisors: 1 7 41 49 287 2009 12613457 88294199 517151737 618059393 3620062159 25340435113