Base | Representation |
---|---|
bin | 10111100110100000… |
… | …011111011101000001 |
3 | 2102102010122202110001 |
4 | 113212200133131001 |
5 | 403400040113401 |
6 | 15350401240001 |
7 | 1555000261060 |
oct | 274640373501 |
9 | 72363582401 |
10 | 25342113601 |
11 | a824a65042 |
12 | 4ab3033001 |
13 | 250b38abbc |
14 | 13259a01d7 |
15 | 9d4c4e601 |
hex | 5e681f741 |
25342113601 has 4 divisors (see below), whose sum is σ = 28962415552. Its totient is φ = 21721811652.
The previous prime is 25342113557. The next prime is 25342113637. The reversal of 25342113601 is 10631124352.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25342113601 - 215 = 25342080833 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 25342113601.
It is not an unprimeable number, because it can be changed into a prime (25342110601) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1810150965 + ... + 1810150978.
It is an arithmetic number, because the mean of its divisors is an integer number (7240603888).
Almost surely, 225342113601 is an apocalyptic number.
It is an amenable number.
25342113601 is a deficient number, since it is larger than the sum of its proper divisors (3620301951).
25342113601 is an equidigital number, since it uses as much as digits as its factorization.
25342113601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3620301950.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 25342113601 its reverse (10631124352), we get a palindrome (35973237953).
The spelling of 25342113601 in words is "twenty-five billion, three hundred forty-two million, one hundred thirteen thousand, six hundred one".
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