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253421504403 = 384473834801
BaseRepresentation
bin1110110000000100011…
…0010100011110010011
3220020010101021021210120
43230001012110132103
513123001401120103
6312230434201323
724211010150154
oct3540106243623
9806111237716
10253421504403
1198525918141
1241146423243
131ab88ba3b02
14c3a0db992b
1568d33bd253
hex3b01194793

253421504403 has 4 divisors (see below), whose sum is σ = 337895339208. Its totient is φ = 168947669600.

The previous prime is 253421504393. The next prime is 253421504477. The reversal of 253421504403 is 304405124352.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 253421504403 - 221 = 253419407251 is a prime.

It is not an unprimeable number, because it can be changed into a prime (253421504603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42236917398 + ... + 42236917403.

It is an arithmetic number, because the mean of its divisors is an integer number (84473834802).

Almost surely, 2253421504403 is an apocalyptic number.

253421504403 is a deficient number, since it is larger than the sum of its proper divisors (84473834805).

253421504403 is an equidigital number, since it uses as much as digits as its factorization.

253421504403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84473834804.

The product of its (nonzero) digits is 57600, while the sum is 33.

Adding to 253421504403 its reverse (304405124352), we get a palindrome (557826628755).

The spelling of 253421504403 in words is "two hundred fifty-three billion, four hundred twenty-one million, five hundred four thousand, four hundred three".

Divisors: 1 3 84473834801 253421504403