25348349083 has 4 divisors (see below), whose sum is σ = 25352666640. Its totient is φ = 25344031528.

The previous prime is 25348349051. The next prime is 25348349099. The reversal of 25348349083 is 38094384352.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25348349083 - 2⁵ = 25348349051 is a prime.

It is a super-4 number, since 4×25348349083⁴ (a number of 43 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25348349003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2149960 + ... + 2161717.

It is an arithmetic number, because the mean of its divisors is an integer number (6338166660).

Almost surely, 2^25348349083 is an apocalyptic number.

25348349083 is a deficient number, since it is larger than the sum of its proper divisors (4317557).

25348349083 is an equidigital number, since it uses as much as digits as its factorization.

25348349083 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4317556.

The product of its (nonzero) digits is 2488320, while the sum is 49.

The spelling of 25348349083 in words is "twenty-five billion, three hundred forty-eight million, three hundred forty-nine thousand, eighty-three".