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25355550007993 = 84518330000071
BaseRepresentation
bin1011100001111100011001…
…00011010010001010111001
310022202222002212122110010111
411300332030203102022321
511310411131300223433
6125532102345144321
75224610111003452
oct560761443221271
9108688085573114
1025355550007993
118096256a64007
122a160aa48b0a1
13111c030a191ca
146393025ca129
152de8519a7dcd
hex170f8c8d22b9

25355550007993 has 4 divisors (see below), whose sum is σ = 25355580853248. Its totient is φ = 25355519162740.

The previous prime is 25355550007903. The next prime is 25355550008017. The reversal of 25355550007993 is 39970005555352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25355550007993 - 241 = 23156526752441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25355550007903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14154853 + ... + 15845218.

It is an arithmetic number, because the mean of its divisors is an integer number (6338895213312).

Almost surely, 225355550007993 is an apocalyptic number.

It is an amenable number.

25355550007993 is a deficient number, since it is larger than the sum of its proper divisors (30845255).

25355550007993 is an equidigital number, since it uses as much as digits as its factorization.

25355550007993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30845254.

The product of its (nonzero) digits is 31893750, while the sum is 58.

The spelling of 25355550007993 in words is "twenty-five trillion, three hundred fifty-five billion, five hundred fifty million, seven thousand, nine hundred ninety-three".

Divisors: 1 845183 30000071 25355550007993