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2536550113 = 14243178091
BaseRepresentation
bin1001011100110000…
…1010111011100001
320112202222002121111
42113030022323201
520143324100423
61055411023321
7116600214556
oct22714127341
96482862544
102536550113
1110918a8709
125a959ab41
13315688936
141a0c46a2d
15eca4a60d
hex9730aee1

2536550113 has 4 divisors (see below), whose sum is σ = 2536742448. Its totient is φ = 2536357780.

The previous prime is 2536550111. The next prime is 2536550131. The reversal of 2536550113 is 3110556352.

2536550113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2536550113 - 21 = 2536550111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2536550111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74803 + ... + 103288.

It is an arithmetic number, because the mean of its divisors is an integer number (634185612).

Almost surely, 22536550113 is an apocalyptic number.

It is an amenable number.

2536550113 is a deficient number, since it is larger than the sum of its proper divisors (192335).

2536550113 is a wasteful number, since it uses less digits than its factorization.

2536550113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192334.

The product of its (nonzero) digits is 13500, while the sum is 31.

The square root of 2536550113 is about 50364.1748964480. The cubic root of 2536550113 is about 1363.7909858881.

The spelling of 2536550113 in words is "two billion, five hundred thirty-six million, five hundred fifty thousand, one hundred thirteen".

Divisors: 1 14243 178091 2536550113