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25380131 = 73625733
BaseRepresentation
bin110000011010…
…0010100100011
31202202102222212
41200310110203
522444131011
62303552335
7425504360
oct140642443
952672885
1025380131
1113365517
1285bb6ab
13534823a
143529467
15236508b
hex1834523

25380131 has 4 divisors (see below), whose sum is σ = 29005872. Its totient is φ = 21754392.

The previous prime is 25380097. The next prime is 25380161. The reversal of 25380131 is 13108352.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25380131 - 218 = 25117987 is a prime.

It is a super-2 number, since 2×253801312 = 1288302099154322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25380097 and 25380106.

It is not an unprimeable number, because it can be changed into a prime (25380161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1812860 + ... + 1812873.

It is an arithmetic number, because the mean of its divisors is an integer number (7251468).

Almost surely, 225380131 is an apocalyptic number.

25380131 is a deficient number, since it is larger than the sum of its proper divisors (3625741).

25380131 is an equidigital number, since it uses as much as digits as its factorization.

25380131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3625740.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 25380131 is about 5037.8696886680. The cubic root of 25380131 is about 293.8763382315.

Adding to 25380131 its reverse (13108352), we get a palindrome (38488483).

The spelling of 25380131 in words is "twenty-five million, three hundred eighty thousand, one hundred thirty-one".

Divisors: 1 7 3625733 25380131