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253820137 = 349172707
BaseRepresentation
bin11110010000011…
…11110011101001
3122200121101202211
433020033303221
51004434221022
641104125121
76201302254
oct1710176351
9580541684
10253820137
1112030290a
12710067a1
134077c43c
14259d209b
151743ae77
hexf20fce9

253820137 has 4 divisors (see below), whose sum is σ = 253896336. Its totient is φ = 253743940.

The previous prime is 253820131. The next prime is 253820179. The reversal of 253820137 is 731028352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-253820137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 253820099 and 253820108.

It is not an unprimeable number, because it can be changed into a prime (253820131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32863 + ... + 39844.

It is an arithmetic number, because the mean of its divisors is an integer number (63474084).

Almost surely, 2253820137 is an apocalyptic number.

It is an amenable number.

253820137 is a deficient number, since it is larger than the sum of its proper divisors (76199).

253820137 is an equidigital number, since it uses as much as digits as its factorization.

253820137 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76198.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 253820137 is about 15931.7336470329. The cubic root of 253820137 is about 633.1530326710.

Adding to 253820137 its reverse (731028352), we get a palindrome (984848489).

The spelling of 253820137 in words is "two hundred fifty-three million, eight hundred twenty thousand, one hundred thirty-seven".

Divisors: 1 3491 72707 253820137