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2539140003 = 32295395539
BaseRepresentation
bin1001011101011000…
…0011001110100011
320112221211200021100
42113112003032203
520200004440003
61055542325443
7116631222351
oct22726031643
96487750240
102539140003
111093307514
125aa429883
1331608470a
141a131c7d1
15ecdacba3
hex975833a3

2539140003 has 12 divisors (see below), whose sum is σ = 3668927080. Its totient is φ = 1692169056.

The previous prime is 2539140001. The next prime is 2539140017. The reversal of 2539140003 is 3000419352.

2539140003 is a `hidden beast` number, since 253 + 9 + 1 + 400 + 0 + 3 = 666.

2539140003 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 2539140003 - 21 = 2539140001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2539140001) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21193 + ... + 74346.

Almost surely, 22539140003 is an apocalyptic number.

2539140003 is a deficient number, since it is larger than the sum of its proper divisors (1129787077).

2539140003 is a wasteful number, since it uses less digits than its factorization.

2539140003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98498 (or 98495 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 27.

The square root of 2539140003 is about 50389.8799661202. The cubic root of 2539140003 is about 1364.2549845012.

Adding to 2539140003 its reverse (3000419352), we get a palindrome (5539559355).

The spelling of 2539140003 in words is "two billion, five hundred thirty-nine million, one hundred forty thousand, three".

Divisors: 1 3 9 2953 8859 26577 95539 286617 859851 282126667 846380001 2539140003