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2540003 = 14917047
BaseRepresentation
bin1001101100000111100011
311210001020012
421230013203
51122240003
6130235135
730406154
oct11540743
94701205
102540003
111485384
12a25aab
136ac17b
144a192b
153528d8
hex26c1e3

2540003 has 4 divisors (see below), whose sum is σ = 2557200. Its totient is φ = 2522808.

The previous prime is 2539997. The next prime is 2540011. The reversal of 2540003 is 3000452.

2540003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2540003 - 218 = 2277859 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2540003.

It is not an unprimeable number, because it can be changed into a prime (2540033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8375 + ... + 8672.

It is an arithmetic number, because the mean of its divisors is an integer number (639300).

22540003 is an apocalyptic number.

2540003 is a deficient number, since it is larger than the sum of its proper divisors (17197).

2540003 is a wasteful number, since it uses less digits than its factorization.

2540003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17196.

The product of its (nonzero) digits is 120, while the sum is 14.

The square root of 2540003 is about 1593.7386862344. The cubic root of 2540003 is about 136.4409526931.

Adding to 2540003 its reverse (3000452), we get a palindrome (5540455).

The spelling of 2540003 in words is "two million, five hundred forty thousand, three".

Divisors: 1 149 17047 2540003