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25400113 = 71935327
BaseRepresentation
bin110000011100…
…1001100110001
31202210110101221
41200321030301
523000300423
62304225041
7425616544
oct140711461
952713357
1025400113
1113379532
12860b181
13535436b
14353285b
15236ae5d
hex1839331

25400113 has 4 divisors (see below), whose sum is σ = 25436160. Its totient is φ = 25364068.

The previous prime is 25400083. The next prime is 25400147. The reversal of 25400113 is 31100452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25400113 - 29 = 25399601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25400513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16945 + ... + 18382.

It is an arithmetic number, because the mean of its divisors is an integer number (6359040).

Almost surely, 225400113 is an apocalyptic number.

It is an amenable number.

25400113 is a deficient number, since it is larger than the sum of its proper divisors (36047).

25400113 is an equidigital number, since it uses as much as digits as its factorization.

25400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36046.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 25400113 is about 5039.8524779997. The cubic root of 25400113 is about 293.9534418075.

Adding to 25400113 its reverse (31100452), we get a palindrome (56500565).

The spelling of 25400113 in words is "twenty-five million, four hundred thousand, one hundred thirteen".

Divisors: 1 719 35327 25400113