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2540110113 = 32881932003
BaseRepresentation
bin1001011101100111…
…0000000100100001
320120000122222000100
42113121300010201
520200232010423
61100015213013
7116642402562
oct22731600441
96500588010
102540110113
11109390a362
125aa817169
13316334148
141a14d2169
15ed000343
hex97670121

2540110113 has 12 divisors (see below), whose sum is σ = 3669578640. Its totient is φ = 1693161816.

The previous prime is 2540110091. The next prime is 2540110121. The reversal of 2540110113 is 3110110452.

2540110113 is a `hidden beast` number, since 2 + 540 + 1 + 10 + 113 = 666.

It is not a de Polignac number, because 2540110113 - 214 = 2540093729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2540110123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 63370 + ... + 95372.

It is an arithmetic number, because the mean of its divisors is an integer number (305798220).

Almost surely, 22540110113 is an apocalyptic number.

It is an amenable number.

2540110113 is a deficient number, since it is larger than the sum of its proper divisors (1129468527).

2540110113 is a wasteful number, since it uses less digits than its factorization.

2540110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40828 (or 40825 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

The square root of 2540110113 is about 50399.5050868558. The cubic root of 2540110113 is about 1364.4287059038.

Adding to 2540110113 its reverse (3110110452), we get a palindrome (5650220565).

The spelling of 2540110113 in words is "two billion, five hundred forty million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 3 9 8819 26457 32003 79371 96009 288027 282234457 846703371 2540110113