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254052131 = 1714944243
BaseRepresentation
bin11110010010010…
…00011100100011
3122201001012000012
433021020130203
51010014132011
641113115135
76203256524
oct1711103443
9581035005
10254052131
11120451143
12710b8aab
1340830c08
1425a5284b
1517484a8b
hexf248723

254052131 has 4 divisors (see below), whose sum is σ = 268996392. Its totient is φ = 239107872.

The previous prime is 254052119. The next prime is 254052157. The reversal of 254052131 is 131250452.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 254052131 - 222 = 249857827 is a prime.

It is a super-2 number, since 2×2540521312 = 129084970531282322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 254052097 and 254052106.

It is not an unprimeable number, because it can be changed into a prime (254052431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7472105 + ... + 7472138.

It is an arithmetic number, because the mean of its divisors is an integer number (67249098).

Almost surely, 2254052131 is an apocalyptic number.

254052131 is a deficient number, since it is larger than the sum of its proper divisors (14944261).

254052131 is a wasteful number, since it uses less digits than its factorization.

254052131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14944260.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 254052131 is about 15939.0128615294. The cubic root of 254052131 is about 633.3458765444.

The spelling of 254052131 in words is "two hundred fifty-four million, fifty-two thousand, one hundred thirty-one".

Divisors: 1 17 14944243 254052131