2540623040113 has 4 divisors (see below), whose sum is σ = 2552015968768. Its totient is φ = 2529230111460.

The previous prime is 2540623040063. The next prime is 2540623040117. The reversal of 2540623040113 is 3110403260452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2540623040113 - 2²¹ = 2540620942961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2540623040117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5696463993 + ... + 5696464438.

It is an arithmetic number, because the mean of its divisors is an integer number (638003992192).

Almost surely, 2^{2540623040113} is an apocalyptic number.

It is an amenable number.

2540623040113 is a deficient number, since it is larger than the sum of its proper divisors (11392928655).

2540623040113 is a wasteful number, since it uses less digits than its factorization.

2540623040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11392928654.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 2540623040113 in words is "two trillion, five hundred forty billion, six hundred twenty-three million, forty thousand, one hundred thirteen".