254131115016001 has 4 divisors (see below), whose sum is σ = 254380507671600. Its totient is φ = 253881722360404.

The previous prime is 254131115015963. The next prime is 254131115016041. The reversal of 254131115016001 is 100610511131452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 254131115016001 - 2¹¹ = 254131115013953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (254131115016041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124696326271 + ... + 124696328308.

It is an arithmetic number, because the mean of its divisors is an integer number (63595126917900).

Almost surely, 2^{254131115016001} is an apocalyptic number.

It is an amenable number.

254131115016001 is a deficient number, since it is larger than the sum of its proper divisors (249392655599).

254131115016001 is a wasteful number, since it uses less digits than its factorization.

254131115016001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 249392655598.

The product of its (nonzero) digits is 3600, while the sum is 31.

Adding to 254131115016001 its reverse (100610511131452), we get a palindrome (354741626147453).

The spelling of 254131115016001 in words is "two hundred fifty-four trillion, one hundred thirty-one billion, one hundred fifteen million, sixteen thousand, one".