Base | Representation |
---|---|
bin | 1110110010110000011… |
… | …0101110010000111011 |
3 | 220021222122221121022002 |
4 | 3230230012232100323 |
5 | 13130441103432311 |
6 | 312430211051215 |
7 | 24234621054251 |
oct | 3545406562073 |
9 | 807878847262 |
10 | 254143030331 |
11 | 9886612a263 |
12 | 41307ba0b0b |
13 | 1ac7250c028 |
14 | c42cb585d1 |
15 | 69268e393b |
hex | 3b2c1ae43b |
254143030331 has 4 divisors (see below), whose sum is σ = 254196103200. Its totient is φ = 254089957464.
The previous prime is 254143030223. The next prime is 254143030369. The reversal of 254143030331 is 133030341452.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 254143030331 - 214 = 254143013947 is a prime.
It is a super-2 number, since 2×2541430303312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 254143030294 and 254143030303.
It is not an unprimeable number, because it can be changed into a prime (254143035331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26529251 + ... + 26538828.
It is an arithmetic number, because the mean of its divisors is an integer number (63549025800).
Almost surely, 2254143030331 is an apocalyptic number.
254143030331 is a deficient number, since it is larger than the sum of its proper divisors (53072869).
254143030331 is an equidigital number, since it uses as much as digits as its factorization.
254143030331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53072868.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 254143030331 its reverse (133030341452), we get a palindrome (387173371783).
The spelling of 254143030331 in words is "two hundred fifty-four billion, one hundred forty-three million, thirty thousand, three hundred thirty-one".
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