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2542131307 = 6613845887
BaseRepresentation
bin1001011110000101…
…1101100001101011
320120011110122120101
42113201131201223
520201241200212
61100130410231
7116665521352
oct22741354153
96504418511
102542131307
111094a6a971
125ab430977
13316891111
141a189a999
15ed29e157
hex9785d86b

2542131307 has 4 divisors (see below), whose sum is σ = 2545977856. Its totient is φ = 2538284760.

The previous prime is 2542131301. The next prime is 2542131313. The reversal of 2542131307 is 7031312452.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (2542131301) and next prime (2542131313).

It is a cyclic number.

It is not a de Polignac number, because 2542131307 - 23 = 2542131299 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2542131301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1922283 + ... + 1923604.

It is an arithmetic number, because the mean of its divisors is an integer number (636494464).

Almost surely, 22542131307 is an apocalyptic number.

2542131307 is a deficient number, since it is larger than the sum of its proper divisors (3846549).

2542131307 is an equidigital number, since it uses as much as digits as its factorization.

2542131307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3846548.

The product of its (nonzero) digits is 5040, while the sum is 28.

The square root of 2542131307 is about 50419.5528242764. The cubic root of 2542131307 is about 1364.7905070135.

Adding to 2542131307 its reverse (7031312452), we get a palindrome (9573443759).

The spelling of 2542131307 in words is "two billion, five hundred forty-two million, one hundred thirty-one thousand, three hundred seven".

Divisors: 1 661 3845887 2542131307