Base | Representation |
---|---|
bin | 1011100100100001011000… |
… | …11010101000011000000011 |
3 | 10100002102202021020102222101 |
4 | 11302100230122220120003 |
5 | 11313334040122041011 |
6 | 130040512252451231 |
7 | 5234164203521605 |
oct | 562205432503003 |
9 | 110072667212871 |
10 | 25444131440131 |
11 | 811a882964068 |
12 | 2a2b2b0179b17 |
13 | 11274a998b401 |
14 | 63d706d41175 |
15 | 2e1cd85232c1 |
hex | 17242c6a8603 |
25444131440131 has 4 divisors (see below), whose sum is σ = 25445510021272. Its totient is φ = 25442752858992.
The previous prime is 25444131440129. The next prime is 25444131440149. The reversal of 25444131440131 is 13104413144452.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 25444131440131 - 21 = 25444131440129 is a prime.
It is a super-2 number, since 2×254441314401312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25444131440831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 689262885 + ... + 689299798.
It is an arithmetic number, because the mean of its divisors is an integer number (6361377505318).
Almost surely, 225444131440131 is an apocalyptic number.
25444131440131 is a deficient number, since it is larger than the sum of its proper divisors (1378581141).
25444131440131 is a wasteful number, since it uses less digits than its factorization.
25444131440131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1378581140.
The product of its (nonzero) digits is 92160, while the sum is 37.
Adding to 25444131440131 its reverse (13104413144452), we get a palindrome (38548544584583).
The spelling of 25444131440131 in words is "twenty-five trillion, four hundred forty-four billion, one hundred thirty-one million, four hundred forty thousand, one hundred thirty-one".
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