Base | Representation |
---|---|
bin | 10111101111111110… |
… | …100110010100101001 |
3 | 2102211012122001222120 |
4 | 113233332212110221 |
5 | 404211224013001 |
6 | 15414234541453 |
7 | 1561636634460 |
oct | 275776462451 |
9 | 72735561876 |
10 | 25501001001 |
11 | a8a6717543 |
12 | 4b38297889 |
13 | 253527c108 |
14 | 133cb1d9d7 |
15 | 9e3b87236 |
hex | 5effa6529 |
25501001001 has 8 divisors (see below), whose sum is σ = 38858668224. Its totient is φ = 14572000560.
The previous prime is 25501000997. The next prime is 25501001023. The reversal of 25501001001 is 10010010552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 25501001001 - 22 = 25501000997 is a prime.
It is a super-3 number, since 3×255010010013 (a number of 32 digits) contains 333 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (25501001101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 607166670 + ... + 607166711.
It is an arithmetic number, because the mean of its divisors is an integer number (4857333528).
Almost surely, 225501001001 is an apocalyptic number.
25501001001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
25501001001 is a deficient number, since it is larger than the sum of its proper divisors (13357667223).
25501001001 is a wasteful number, since it uses less digits than its factorization.
25501001001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1214333391.
The product of its (nonzero) digits is 50, while the sum is 15.
Adding to 25501001001 its reverse (10010010552), we get a palindrome (35511011553).
The spelling of 25501001001 in words is "twenty-five billion, five hundred one million, one thousand, one".
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