Base | Representation |
---|---|
bin | 1001011111111111… |
… | …1011000000111001 |
3 | 20120201111100001220 |
4 | 2113333323000321 |
5 | 20210312211114 |
6 | 1101013502253 |
7 | 120123426501 |
oct | 22777730071 |
9 | 6521440056 |
10 | 2550116409 |
11 | 1099524225 |
12 | 5b2041989 |
13 | 318428829 |
14 | 1a2978a01 |
15 | edd2a0a9 |
hex | 97ffb039 |
2550116409 has 4 divisors (see below), whose sum is σ = 3400155216. Its totient is φ = 1700077604.
The previous prime is 2550116381. The next prime is 2550116423. The reversal of 2550116409 is 9046110552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2550116409 - 211 = 2550114361 is a prime.
It is a super-3 number, since 3×25501164093 (a number of 29 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2550116409.
It is not an unprimeable number, because it can be changed into a prime (2550116489) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425019399 + ... + 425019404.
It is an arithmetic number, because the mean of its divisors is an integer number (850038804).
Almost surely, 22550116409 is an apocalyptic number.
It is an amenable number.
2550116409 is a deficient number, since it is larger than the sum of its proper divisors (850038807).
2550116409 is an equidigital number, since it uses as much as digits as its factorization.
2550116409 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850038806.
The product of its (nonzero) digits is 10800, while the sum is 33.
The square root of 2550116409 is about 50498.6772995095. The cubic root of 2550116409 is about 1366.2179969663.
The spelling of 2550116409 in words is "two billion, five hundred fifty million, one hundred sixteen thousand, four hundred nine".
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