255014331334241 has 4 divisors (see below), whose sum is σ = 255014887526400. Its totient is φ = 255013775142084.

The previous prime is 255014331334211. The next prime is 255014331334247. The reversal of 255014331334241 is 142433133410552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255014331334241 - 2²² = 255014327139937 is a prime.

It is a super-2 number, since 2×255014331334241² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255014331334247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 277407761 + ... + 278325518.

It is an arithmetic number, because the mean of its divisors is an integer number (63753721881600).

Almost surely, 2^{255014331334241} is an apocalyptic number.

It is an amenable number.

255014331334241 is a deficient number, since it is larger than the sum of its proper divisors (556192159).

255014331334241 is an equidigital number, since it uses as much as digits as its factorization.

255014331334241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 556192158.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 255014331334241 its reverse (142433133410552), we get a palindrome (397447464744793).

The spelling of 255014331334241 in words is "two hundred fifty-five trillion, fourteen billion, three hundred thirty-one million, three hundred thirty-four thousand, two hundred forty-one".