Base | Representation |
---|---|
bin | 1110110110000100001… |
… | …1101000000101100001 |
3 | 220101021120121000112100 |
4 | 3231201003220011201 |
5 | 13134301020123131 |
6 | 313054304121013 |
7 | 24265626140421 |
oct | 3554103500541 |
9 | 811246530470 |
10 | 255031411041 |
11 | 991816458a0 |
12 | 41515606169 |
13 | 1b084597aa4 |
14 | c4b4b2c481 |
15 | 69798c77e6 |
hex | 3b610e8161 |
255031411041 has 36 divisors (see below), whose sum is σ = 415249482960. Its totient is φ = 149578484400.
The previous prime is 255031411027. The next prime is 255031411073. The reversal of 255031411041 is 140114130552.
255031411041 is a `hidden beast` number, since 2 + 5 + 503 + 1 + 4 + 110 + 41 = 666.
It is not a de Polignac number, because 255031411041 - 25 = 255031411009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255031410996 and 255031411014.
It is not an unprimeable number, because it can be changed into a prime (255031411841) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1245171 + ... + 1435448.
It is an arithmetic number, because the mean of its divisors is an integer number (11534707860).
Almost surely, 2255031411041 is an apocalyptic number.
It is an amenable number.
255031411041 is a deficient number, since it is larger than the sum of its proper divisors (160218071919).
255031411041 is a wasteful number, since it uses less digits than its factorization.
255031411041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2680698 (or 2680664 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 255031411041 its reverse (140114130552), we get a palindrome (395145541593).
The spelling of 255031411041 in words is "two hundred fifty-five billion, thirty-one million, four hundred eleven thousand, forty-one".
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