Base | Representation |
---|---|
bin | 100101000111010000011… |
… | …001110001000100010011 |
3 | 100000211001121011121210211 |
4 | 211013100121301010103 |
5 | 313241220434201120 |
6 | 5231350524504551 |
7 | 352155405332533 |
oct | 45072031610423 |
9 | 10024047147724 |
10 | 2550412022035 |
11 | 8a3695108609 |
12 | 3523539ab157 |
13 | 15666c912487 |
14 | 8b6250174c3 |
15 | 4651e74125a |
hex | 251d0671113 |
2550412022035 has 16 divisors (see below), whose sum is σ = 3103673699520. Its totient is φ = 2011544801280.
The previous prime is 2550412022023. The next prime is 2550412022209. The reversal of 2550412022035 is 5302202140552.
It is not a de Polignac number, because 2550412022035 - 213 = 2550412013843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2550412021988 and 2550412022006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26773771 + ... + 26868859.
It is an arithmetic number, because the mean of its divisors is an integer number (193979606220).
Almost surely, 22550412022035 is an apocalyptic number.
2550412022035 is a deficient number, since it is larger than the sum of its proper divisors (553261677485).
2550412022035 is an equidigital number, since it uses as much as digits as its factorization.
2550412022035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170718.
The product of its (nonzero) digits is 24000, while the sum is 31.
Adding to 2550412022035 its reverse (5302202140552), we get a palindrome (7852614162587).
The spelling of 2550412022035 in words is "two trillion, five hundred fifty billion, four hundred twelve million, twenty-two thousand, thirty-five".
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