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2551101411 = 31151973823
BaseRepresentation
bin1001100000001110…
…1011011111100011
320120210100101020110
42120003223133203
520211040221121
61101050542403
7120135001305
oct23003533743
96523311213
102551101411
11109a037281
125b2437a03
133186b1c81
141a2b53975
15ede71d76
hex980eb7e3

2551101411 has 8 divisors (see below), whose sum is σ = 3401809920. Its totient is φ = 1700563592.

The previous prime is 2551101407. The next prime is 2551101431. The reversal of 2551101411 is 1141011552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2551101411 - 22 = 2551101407 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2551101431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2355 + ... + 71468.

It is an arithmetic number, because the mean of its divisors is an integer number (425226240).

Almost surely, 22551101411 is an apocalyptic number.

2551101411 is a deficient number, since it is larger than the sum of its proper divisors (850708509).

2551101411 is a wasteful number, since it uses less digits than its factorization.

2551101411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85345.

The product of its (nonzero) digits is 200, while the sum is 21.

The square root of 2551101411 is about 50508.4291084171. The cubic root of 2551101411 is about 1366.3938783791.

Adding to 2551101411 its reverse (1141011552), we get a palindrome (3692112963).

The spelling of 2551101411 in words is "two billion, five hundred fifty-one million, one hundred one thousand, four hundred eleven".

Divisors: 1 3 11519 34557 73823 221469 850367137 2551101411